किस स्थिति में \(x^2+px+q\) के शून्यक \(4+\sqrt{7}\) और \(4-\sqrt{7}\) होंगे?
In which case will \(x^2+px+q\) have zeroes \(4+\sqrt{7}\) and \(4-\sqrt{7}\)?
Explanation opens after your attempt
Correct Answer
A. (p=-8, q=9)
Concept
The sum is (8), so (p=-8), and the product is (16-7=9). In a monic polynomial, (p=-) sum.
Why this answer is correct
The correct answer is A. (p=-8, q=9). The sum is (8), so (p=-8), and the product is (16-7=9). In a monic polynomial, (p=-) sum.
Exam Tip
योग (8) है, इसलिए (p=-8), और गुणनफल (16-7=9) है। एकक बहुपद में (p=-) योग होता है।
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