Concept-wise Practice

downward parabola MCQ Questions for Class 10

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Practice Questions

5 questions tagged with downward parabola.

Question 1/5 Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि नीचे खुलने वाले परवलय के शून्यक (-5) और (13) हैं, तो (x=2) पर ग्राफ कहाँ होगा?

If a downward-opening parabola has zeroes (-5) and (13), where will the graph be at (x=2)?

Explanation opens after your attempt
Correct Answer

A. (x)-अक्ष के ऊपरAbove the (x)-axis

Step 1

Concept

For a downward-opening parabola, values between the two zeroes are positive. Tip: (x=2) lies between the zeroes.

Step 2

Why this answer is correct

The correct answer is A. (x)-अक्ष के ऊपर / Above the (x)-axis. For a downward-opening parabola, values between the two zeroes are positive. Tip: (x=2) lies between the zeroes.

Step 3

Exam Tip

नीचे खुलने वाले परवलय में दो शून्यकों के बीच मान धनात्मक होते हैं। टिप: (x=2) दोनों शून्यकों के बीच है।

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Question 2/5 Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि नीचे खुलने वाले परवलय के शून्यक (-3) और (11) हैं, तो (x=4) पर ग्राफ कहाँ होगा?

If a downward-opening parabola has zeroes (-3) and (11), where will the graph be at (x=4)?

Explanation opens after your attempt
Correct Answer

A. (x)-अक्ष के ऊपरAbove the (x)-axis

Step 1

Concept

For a downward-opening parabola, values between the two zeroes are positive. Tip: (x=4) lies between the zeroes.

Step 2

Why this answer is correct

The correct answer is A. (x)-अक्ष के ऊपर / Above the (x)-axis. For a downward-opening parabola, values between the two zeroes are positive. Tip: (x=4) lies between the zeroes.

Step 3

Exam Tip

नीचे खुलने वाले परवलय में दो शून्यकों के बीच मान धनात्मक होते हैं। टिप: (x=4) दोनों शून्यकों के बीच है।

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Question 3/5 Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि परवलय के शून्यक (-4) और (10) हैं तथा वह नीचे की ओर खुलता है तो शून्यकों के बाहर ग्राफ कहाँ होगा?

If a parabola has zeroes (-4) and (10) and opens downward, where will the graph be outside the zeroes?

Explanation opens after your attempt
Correct Answer

B. (x)-अक्ष के नीचेBelow the (x)-axis

Step 1

Concept

For a downward-opening parabola, values outside the zeroes are negative. Tip: opening direction changes sign regions.

Step 2

Why this answer is correct

The correct answer is B. (x)-अक्ष के नीचे / Below the (x)-axis. For a downward-opening parabola, values outside the zeroes are negative. Tip: opening direction changes sign regions.

Step 3

Exam Tip

नीचे खुलने वाले परवलय में शून्यकों के बाहर मान ऋणात्मक होते हैं। टिप: खुलने की दिशा संकेत क्षेत्र बदलती है।

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Question 4/5 Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि परवलय के शून्यक (-2) और (8) हैं तथा वह नीचे की ओर खुलता है, तो शून्यकों के बाहर ग्राफ कहाँ होगा?

If a parabola has zeroes (-2) and (8) and opens downward, where will the graph be outside the zeroes?

Explanation opens after your attempt
Correct Answer

B. (x)-अक्ष के नीचेBelow the (x)-axis

Step 1

Concept

For a downward-opening parabola, values outside the zeroes are negative. Tip: opening direction changes sign regions.

Step 2

Why this answer is correct

The correct answer is B. (x)-अक्ष के नीचे / Below the (x)-axis. For a downward-opening parabola, values outside the zeroes are negative. Tip: opening direction changes sign regions.

Step 3

Exam Tip

नीचे खुलने वाले परवलय में शून्यकों के बाहर मान ऋणात्मक होते हैं। टिप: खुलने की दिशा संकेत क्षेत्र बदलती है।

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Question 5/5 Medium Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=-x-2+25), तो ग्राफ के वास्तविक शून्यक कौन से होंगे?

If (p(x)=-x-2+25), what will be the real zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (5) और (-5)(5) and (-5)

Step 1

Concept

From \(-x^2+25=0\), \(x^2=25\), so \(x=\pm5\). Tip: even with a negative sign, set (y=0).

Step 2

Why this answer is correct

The correct answer is A. (5) और (-5) / (5) and (-5). From \(-x^2+25=0\), \(x^2=25\), so \(x=\pm5\). Tip: even with a negative sign, set (y=0).

Step 3

Exam Tip

\(-x^2+25=0\) से \(x^2=25\), इसलिए \(x=\pm5\) है। टिप: ऋण चिह्न देखकर भी (y=0) रखना न भूलें।

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