Concept-wise Practice

division by 15 MCQ Questions for Class 10

division by 15 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with division by 15.

Question 1/3 Easy Mathematics Chapter 1: Real Numbers 1: Euclid’s Division Lemma Class 10 Level 3

यदि (112) को (15) से भाग दें तो सही भागफल क्या होगा?

What is the correct quotient when (112) is divided by (15)?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

\(15 \times 7=105\) and \(15 \times 8=120\).

Step 2

Why this answer is correct

(120) is greater than (112), so the quotient is (7).

Step 3

Exam Tip

While choosing the quotient, do not take a multiple greater than the dividend. चरण 1: \(15 \times 7=105\) और \(15 \times 8=120\) है। चरण 2: (120), (112) से बड़ा है, इसलिए भागफल (7) होगा। चरण 3: भागफल चुनते समय भाज्य से बड़ा गुणज नहीं लेना चाहिए।

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Question 2/3 Easy Mathematics Chapter 1: Real Numbers 1: Euclid’s Division Lemma Class 10 Level 3

यदि (112) को (15) से भाग दें तो सही शेषफल क्या होगा?

What is the correct remainder when (112) is divided by (15)?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

\(15 \times 7=105\).

Step 2

Why this answer is correct

(112-105=7), so the remainder is (7).

Step 3

Exam Tip

The remainder is less than (15), so the answer is correct. चरण 1: \(15 \times 7=105\) है। चरण 2: (112-105=7), इसलिए शेषफल (7) है। चरण 3: शेषफल (15) से छोटा है, इसलिए उत्तर सही है।

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Question 3/3 Easy Mathematics Chapter 1: Real Numbers 1: Euclid’s Division Lemma Class 10 Level 1

यदि किसी संख्या को (15) से भाग दें तो सबसे बड़ा संभव शेषफल क्या होगा?

If a number is divided by (15), what is the greatest possible remainder?

Explanation opens after your attempt
Correct Answer

A. (14)

Step 1

Concept

The rule for the remainder is \(0 \le r < 15\).

Step 2

Why this answer is correct

Therefore, the greatest possible remainder is (14).

Step 3

Exam Tip

The greatest remainder is always one less than the divisor. चरण 1: शेषफल के लिए नियम \(0 \le r < 15\) है। चरण 2: इसलिए सबसे बड़ा संभव शेषफल (14) होगा। चरण 3: सबसे बड़ा शेषफल हमेशा भाजक से एक कम होता है।

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