Concept-wise Practice

divisibility-denominator MCQ Questions for Class 9

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Practice Questions

2 questions tagged with divisibility-denominator.

\(\sqrt{3}\) के प्रमाण में \(q^2=3k^2\) मिलने पर (q) के बारे में कौन-सा निष्कर्ष सही है?

In the proof of \(\sqrt{3}\), after getting \(q^2=3k^2\), which conclusion about (q) is correct?

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Correct Answer

D. (q) (3) से विभाज्य है(q) is divisible by (3)

Step 1

Concept

\(q^2\) is divisible by (3), so (q) is also divisible by (3). This leads to the final contradiction.

Step 2

Why this answer is correct

The correct answer is D. (q) (3) से विभाज्य है / (q) is divisible by (3). \(q^2\) is divisible by (3), so (q) is also divisible by (3). This leads to the final contradiction.

Step 3

Exam Tip

\(q^2\) (3) से विभाज्य है इसलिए (q) भी (3) से विभाज्य होगा। यह अंतिम विरोधाभास की ओर ले जाता है।

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यदि \(p^2=3q^2\) और (p=3k) है तो (q) (3) से विभाज्य क्यों होगा?

If \(p^2=3q^2\) and (p=3k), why will (q) be divisible by (3)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि \(q^2=3k^2\) से \(q^2\) (3) से विभाज्य हैBecause \(q^2=3k^2\) makes \(q^2\) divisible by (3)

Step 1

Concept

After getting \(q^2=3k^2\), \(q^2\) is divisible by (3). Therefore (q) is also divisible by (3).

Step 2

Why this answer is correct

The correct answer is A. क्योंकि \(q^2=3k^2\) से \(q^2\) (3) से विभाज्य है / Because \(q^2=3k^2\) makes \(q^2\) divisible by (3). After getting \(q^2=3k^2\), \(q^2\) is divisible by (3). Therefore (q) is also divisible by (3).

Step 3

Exam Tip

\(q^2=3k^2\) मिलने पर \(q^2\) (3) से विभाज्य है। इसलिए (q) भी (3) से विभाज्य है।

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