Concept-wise Practice

class 11 MCQ Questions for Class 11

class 11 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2918 questions tagged with class 11.

\(\frac{(n+2)!}{(n+1)!}\times\frac{(n+1)!}{n!}\) का सरल रूप क्या है?

What is the simplified form of \(\frac{(n+2)!}{(n+1)!}\times\frac{(n+1)!}{n!}\)?

Explanation opens after your attempt
Correct Answer

B. ((n+2)(n+1))

Step 1

Concept

The first ratio is (n+2) and the second is (n+1). The product is ((n+2)(n+1)).

Step 2

Why this answer is correct

The correct answer is B. ((n+2)(n+1)). The first ratio is (n+2) and the second is (n+1). The product is ((n+2)(n+1)).

Step 3

Exam Tip

पहला अनुपात (n+2) और दूसरा (n+1) है। गुणनफल ((n+2)(n+1)) होगा।

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\(\frac{7!}{5!}+\frac{5!}{2!,3!}+1!\) का मान क्या है?

What is the value of \(\frac{7!}{5!}+\frac{5!}{2!,3!}+1!\)?

Explanation opens after your attempt
Correct Answer

C. (53)

Step 1

Concept

\(\frac{7!}{5!}=42\), \(\frac{5!}{2!,3!}=10\), and (1!=1). The total is (53).

Step 2

Why this answer is correct

The correct answer is C. (53). \(\frac{7!}{5!}=42\), \(\frac{5!}{2!,3!}=10\), and (1!=1). The total is (53).

Step 3

Exam Tip

\(\frac{7!}{5!}=42\), \(\frac{5!}{2!,3!}=10\) और (1!=1)। कुल (53) है।

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यदि (\frac{(n+4)!}{(n+2)!}=132), तो (n) का मान क्या है?

If (\frac{(n+4)!}{(n+2)!}=132), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

(\frac{(n+4)!}{(n+2)!}=(n+4)(n+3)). Since \(12\times11=132\), (n=8).

Step 2

Why this answer is correct

The correct answer is B. (8). (\frac{(n+4)!}{(n+2)!}=(n+4)(n+3)). Since \(12\times11=132\), (n=8).

Step 3

Exam Tip

(\frac{(n+4)!}{(n+2)!}=(n+4)(n+3))। \(12\times11=132\), इसलिए (n=8) है।

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(\frac{(n+5)!}{(n+2)!}) का सरल रूप क्या है?

What is the simplified form of (\frac{(n+5)!}{(n+2)!})?

Explanation opens after your attempt
Correct Answer

B. ((n+5)(n+4)(n+3))

Step 1

Concept

((n+5)!=(n+5)(n+4)(n+3)(n+2)!). Therefore three factors remain.

Step 2

Why this answer is correct

The correct answer is B. ((n+5)(n+4)(n+3)). ((n+5)!=(n+5)(n+4)(n+3)(n+2)!). Therefore three factors remain.

Step 3

Exam Tip

((n+5)!=(n+5)(n+4)(n+3)(n+2)!)। इसलिए तीन गुणक बचते हैं।

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\(\frac{11!}{8!,3!}-\frac{9!}{7!,2!}\) का मान क्या है?

What is the value of \(\frac{11!}{8!,3!}-\frac{9!}{7!,2!}\)?

Explanation opens after your attempt
Correct Answer

C. (129)

Step 1

Concept

The first term is (165) and the second is (36). The difference is (129).

Step 2

Why this answer is correct

The correct answer is C. (129). The first term is (165) and the second is (36). The difference is (129).

Step 3

Exam Tip

पहला पद (165) और दूसरा (36) है। अंतर (129) मिलेगा।

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\(4!\times\frac{6!}{5!}-3!\) का मान क्या है?

What is the value of \(4!\times\frac{6!}{5!}-3!\)?

Explanation opens after your attempt
Correct Answer

C. (138)

Step 1

Concept

(4!=24), \(\frac{6!}{5!}=6\), and (3!=6). Hence \(24\times6-6=138\).

Step 2

Why this answer is correct

The correct answer is C. (138). (4!=24), \(\frac{6!}{5!}=6\), and (3!=6). Hence \(24\times6-6=138\).

Step 3

Exam Tip

(4!=24), \(\frac{6!}{5!}=6\) और (3!=6)। इसलिए \(24\times6-6=138\) है।

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\(\frac{10!-8!}{8!}\) का मान क्या है?

What is the value of \(\frac{10!-8!}{8!}\)?

Explanation opens after your attempt
Correct Answer

C. (89)

Step 1

Concept

\(\frac{10!}{8!}=90\) and \(\frac{8!}{8!}=1\). Therefore the value is (90-1=89).

Step 2

Why this answer is correct

The correct answer is C. (89). \(\frac{10!}{8!}=90\) and \(\frac{8!}{8!}=1\). Therefore the value is (90-1=89).

Step 3

Exam Tip

\(\frac{10!}{8!}=90\) और \(\frac{8!}{8!}=1\)। इसलिए मान (90-1=89) है।

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(\frac{(n+3)!+(n+2)!}{(n+2)!}) का सरल रूप क्या है?

What is the simplified form of (\frac{(n+3)!+(n+2)!}{(n+2)!})?

Explanation opens after your attempt
Correct Answer

C. (n+4)

Step 1

Concept

The numerator is ((n+2)![(n+3)+1]). Therefore the simplified form is (n+4).

Step 2

Why this answer is correct

The correct answer is C. (n+4). The numerator is ((n+2)![(n+3)+1]). Therefore the simplified form is (n+4).

Step 3

Exam Tip

अंश ((n+2)![(n+3)+1]) है। इसलिए सरल रूप (n+4) है।

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\(\frac{\frac{12!}{9!,3!}}{\frac{5!}{3!,2!}}\) का मान क्या है?

What is the value of \(\frac{\frac{12!}{9!,3!}}{\frac{5!}{3!,2!}}\)?

Explanation opens after your attempt
Correct Answer

C. (22)

Step 1

Concept

The numerator term is (220) and the denominator term is (10). Dividing gives (22).

Step 2

Why this answer is correct

The correct answer is C. (22). The numerator term is (220) and the denominator term is (10). Dividing gives (22).

Step 3

Exam Tip

ऊपर का पद (220) और नीचे का पद (10) है। भाग देने पर (22) मिलता है।

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यदि (\frac{(n+1)!}{(n-2)!}=60), तो (n) का मान क्या है?

If (\frac{(n+1)!}{(n-2)!}=60), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

(\frac{(n+1)!}{(n-2)!}=(n+1)n(n-1)). Since \(5\times4\times3=60\), (n=4).

Step 2

Why this answer is correct

The correct answer is B. (4). (\frac{(n+1)!}{(n-2)!}=(n+1)n(n-1)). Since \(5\times4\times3=60\), (n=4).

Step 3

Exam Tip

(\frac{(n+1)!}{(n-2)!}=(n+1)n(n-1))। \(5\times4\times3=60\), इसलिए (n=4) है।

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यदि \(a=\frac{7!-5!}{5!}\), तो (a) का मान क्या है?

If \(a=\frac{7!-5!}{5!}\), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (41)

Step 1

Concept

\(\frac{7!}{5!}=42\) and \(\frac{5!}{5!}=1\). Therefore (a=42-1=41).

Step 2

Why this answer is correct

The correct answer is B. (41). \(\frac{7!}{5!}=42\) and \(\frac{5!}{5!}=1\). Therefore (a=42-1=41).

Step 3

Exam Tip

\(\frac{7!}{5!}=42\) और \(\frac{5!}{5!}=1\)। इसलिए (a=42-1=41) है।

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(\frac{\frac{(n+4)!}{n!}}{\frac{(n+2)!}{n!}}) का सरल रूप क्या है?

What is the simplified form of (\frac{\frac{(n+4)!}{n!}}{\frac{(n+2)!}{n!}})?

Explanation opens after your attempt
Correct Answer

B. ((n+4)(n+3))

Step 1

Concept

This division becomes (\frac{(n+4)!}{(n+2)!}). Hence the simplified form is ((n+4)(n+3)).

Step 2

Why this answer is correct

The correct answer is B. ((n+4)(n+3)). This division becomes (\frac{(n+4)!}{(n+2)!}). Hence the simplified form is ((n+4)(n+3)).

Step 3

Exam Tip

यह भाग (\frac{(n+4)!}{(n+2)!}) बन जाता है। इसलिए सरल रूप ((n+4)(n+3)) है।

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\(\frac{6!}{3!,3!}+\frac{7!}{5!,2!}\) का मान क्या है?

What is the value of \(\frac{6!}{3!,3!}+\frac{7!}{5!,2!}\)?

Explanation opens after your attempt
Correct Answer

C. (41)

Step 1

Concept

The first term is (20) and the second is (21). Their sum is (41).

Step 2

Why this answer is correct

The correct answer is C. (41). The first term is (20) and the second is (21). Their sum is (41).

Step 3

Exam Tip

पहला पद (20) और दूसरा (21) है। दोनों का योग (41) होगा।

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\(\frac{9!+8!}{7!}\) का मान क्या है?

What is the value of \(\frac{9!+8!}{7!}\)?

Explanation opens after your attempt
Correct Answer

B. (80)

Step 1

Concept

The numerator can be written as (8!(9+1)). Thus \(\frac{10\cdot8!}{7!}=10\times8=80\).

Step 2

Why this answer is correct

The correct answer is B. (80). The numerator can be written as (8!(9+1)). Thus \(\frac{10\cdot8!}{7!}=10\times8=80\).

Step 3

Exam Tip

अंश को (8!(9+1)) लिखा जा सकता है। \(\frac{10\cdot8!}{7!}=10\times8=80\) है।

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यदि (\frac{n!}{(n-3)!}=210), तो (n) का मान क्या है?

If (\frac{n!}{(n-3)!}=210), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

(\frac{n!}{(n-3)!}=n(n-1)(n-2)). Since \(7\times6\times5=210\), (n=7).

Step 2

Why this answer is correct

The correct answer is B. (7). (\frac{n!}{(n-3)!}=n(n-1)(n-2)). Since \(7\times6\times5=210\), (n=7).

Step 3

Exam Tip

(\frac{n!}{(n-3)!}=n(n-1)(n-2))। \(7\times6\times5=210\), इसलिए (n=7) है।

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\(\frac{n!}{(n-1)!}\times\frac{(n+1)!}{n!}\) का सरल रूप क्या है?

What is the simplified form of \(\frac{n!}{(n-1)!}\times\frac{(n+1)!}{n!}\)?

Explanation opens after your attempt
Correct Answer

C. (n(n+1))

Step 1

Concept

The first ratio is (n) and the second is (n+1). Therefore the product is (n(n+1)).

Step 2

Why this answer is correct

The correct answer is C. (n(n+1)). The first ratio is (n) and the second is (n+1). Therefore the product is (n(n+1)).

Step 3

Exam Tip

पहला अनुपात (n) और दूसरा (n+1) है। इसलिए गुणनफल (n(n+1)) है।

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\(\frac{10!}{8!}+\frac{7!}{6!}+0!\) का मान क्या है?

What is the value of \(\frac{10!}{8!}+\frac{7!}{6!}+0!\)?

Explanation opens after your attempt
Correct Answer

C. (98)

Step 1

Concept

\(\frac{10!}{8!}=90\), \(\frac{7!}{6!}=7\), and (0!=1). The total is (98).

Step 2

Why this answer is correct

The correct answer is C. (98). \(\frac{10!}{8!}=90\), \(\frac{7!}{6!}=7\), and (0!=1). The total is (98).

Step 3

Exam Tip

\(\frac{10!}{8!}=90\), \(\frac{7!}{6!}=7\) और (0!=1)। कुल (98) है।

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(\frac{(n+2)!-n!}{n!}) का सरल रूप क्या है?

What is the simplified form of (\frac{(n+2)!-n!}{n!})?

Explanation opens after your attempt
Correct Answer

B. \(n^2+3n+1\)

Step 1

Concept

(\frac{(n+2)!}{n!}=(n+2)(n+1)), then (1) is subtracted. The simplified form is \(n^2+3n+1\).

Step 2

Why this answer is correct

The correct answer is B. \(n^2+3n+1\). (\frac{(n+2)!}{n!}=(n+2)(n+1)), then (1) is subtracted. The simplified form is \(n^2+3n+1\).

Step 3

Exam Tip

(\frac{(n+2)!}{n!}=(n+2)(n+1)), फिर (1) घटेगा। सरल रूप \(n^2+3n+1\) है।

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\(\frac{13!}{11!,2!}-\frac{6!}{4!,2!}\) का मान क्या है?

What is the value of \(\frac{13!}{11!,2!}-\frac{6!}{4!,2!}\)?

Explanation opens after your attempt
Correct Answer

C. (63)

Step 1

Concept

The first term is (78) and the second term is (15). The difference is (78-15=63).

Step 2

Why this answer is correct

The correct answer is C. (63). The first term is (78) and the second term is (15). The difference is (78-15=63).

Step 3

Exam Tip

पहला पद (78) और दूसरा पद (15) है। अंतर (78-15=63) है।

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यदि (\frac{(n+3)!}{(n+1)!}=90), तो (n) का मान क्या है?

If (\frac{(n+3)!}{(n+1)!}=90), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

(\frac{(n+3)!}{(n+1)!}=(n+3)(n+2)). Since \(10\times9=90\), (n=7).

Step 2

Why this answer is correct

The correct answer is B. (7). (\frac{(n+3)!}{(n+1)!}=(n+3)(n+2)). Since \(10\times9=90\), (n=7).

Step 3

Exam Tip

(\frac{(n+3)!}{(n+1)!}=(n+3)(n+2))। \(10\times9=90\), इसलिए (n=7) है।

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(\frac{(n+5)!}{(n+2)!}) में कितने क्रमागत गुणक बचते हैं?

How many consecutive factors remain in (\frac{(n+5)!}{(n+2)!})?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

(\frac{(n+5)!}{(n+2)!}=(n+5)(n+4)(n+3)). Therefore three consecutive factors remain.

Step 2

Why this answer is correct

The correct answer is B. (3). (\frac{(n+5)!}{(n+2)!}=(n+5)(n+4)(n+3)). Therefore three consecutive factors remain.

Step 3

Exam Tip

(\frac{(n+5)!}{(n+2)!}=(n+5)(n+4)(n+3))। इसलिए तीन क्रमागत गुणक बचते हैं।

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\(\frac{8!}{5!}+\frac{6!}{4!}-4!\) का मान क्या है?

What is the value of \(\frac{8!}{5!}+\frac{6!}{4!}-4!\)?

Explanation opens after your attempt
Correct Answer

D. (342)

Step 1

Concept

\(\frac{8!}{5!}=336\), \(\frac{6!}{4!}=30\), and (4!=24). Thus (336+30-24=342).

Step 2

Why this answer is correct

The correct answer is D. (342). \(\frac{8!}{5!}=336\), \(\frac{6!}{4!}=30\), and (4!=24). Thus (336+30-24=342).

Step 3

Exam Tip

\(\frac{8!}{5!}=336\), \(\frac{6!}{4!}=30\) और (4!=24)। इसलिए (336+30-24=342) है।

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\(\frac{5!,3!}{2!,4!}\) का मान क्या है?

What is the value of \(\frac{5!,3!}{2!,4!}\)?

Explanation opens after your attempt
Correct Answer

C. (15)

Step 1

Concept

\(\frac{5!}{4!}=5\) and \(\frac{3!}{2!}=3\). Hence the value is \(5\times3=15\).

Step 2

Why this answer is correct

The correct answer is C. (15). \(\frac{5!}{4!}=5\) and \(\frac{3!}{2!}=3\). Hence the value is \(5\times3=15\).

Step 3

Exam Tip

\(\frac{5!}{4!}=5\) और \(\frac{3!}{2!}=3\)। इसलिए मान \(5\times3=15\) है।

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यदि (\frac{(n+1)!}{(n-1)!}=72), तो (n) का मान क्या है?

If (\frac{(n+1)!}{(n-1)!}=72), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

The ratio equals (n(n+1)). Since \(8\times9=72\), (n=8).

Step 2

Why this answer is correct

The correct answer is C. (8). The ratio equals (n(n+1)). Since \(8\times9=72\), (n=8).

Step 3

Exam Tip

अनुपात (n(n+1)) के बराबर है। \(8\times9=72\), इसलिए (n=8) है।

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\(\frac{9!}{7!}\div\frac{6!}{5!}\) का मान क्या है?

What is the value of \(\frac{9!}{7!}\div\frac{6!}{5!}\)?

Explanation opens after your attempt
Correct Answer

B. (12)

Step 1

Concept

\(\frac{9!}{7!}=72\) and \(\frac{6!}{5!}=6\). Therefore the quotient is (12).

Step 2

Why this answer is correct

The correct answer is B. (12). \(\frac{9!}{7!}=72\) and \(\frac{6!}{5!}=6\). Therefore the quotient is (12).

Step 3

Exam Tip

\(\frac{9!}{7!}=72\) और \(\frac{6!}{5!}=6\)। इसलिए भागफल (12) है।

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\(\frac{11!-10!}{9!}\) का मान क्या है?

What is the value of \(\frac{11!-10!}{9!}\)?

Explanation opens after your attempt
Correct Answer

C. (100)

Step 1

Concept

The numerator is (10!(11-1)=10\cdot10!). Thus \(\frac{10\cdot10!}{9!}=10\times10=100\).

Step 2

Why this answer is correct

The correct answer is C. (100). The numerator is (10!(11-1)=10\cdot10!). Thus \(\frac{10\cdot10!}{9!}=10\times10=100\).

Step 3

Exam Tip

अंश (10!(11-1)=10\cdot10!) है। \(\frac{10\cdot10!}{9!}=10\times10=100\) है।

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(\frac{(n+5)!}{(n+3)!}) का सरल रूप क्या है?

What is the simplified form of (\frac{(n+5)!}{(n+3)!})?

Explanation opens after your attempt
Correct Answer

A. ((n+5)(n+4))

Step 1

Concept

((n+5)!=(n+5)(n+4)(n+3)!). Therefore the simplified form is ((n+5)(n+4)).

Step 2

Why this answer is correct

The correct answer is A. ((n+5)(n+4)). ((n+5)!=(n+5)(n+4)(n+3)!). Therefore the simplified form is ((n+5)(n+4)).

Step 3

Exam Tip

((n+5)!=(n+5)(n+4)(n+3)!)। इसलिए सरल रूप ((n+5)(n+4)) है।

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यदि \(x=\frac{8!}{6!}\) और \(y=\frac{5!}{3!}\), तो (x+y) का मान क्या है?

If \(x=\frac{8!}{6!}\) and \(y=\frac{5!}{3!}\), what is the value of (x+y)?

Explanation opens after your attempt
Correct Answer

C. (76)

Step 1

Concept

\(x=8\times7=56\) and \(y=5\times4=20\). Therefore (x+y=76).

Step 2

Why this answer is correct

The correct answer is C. (76). \(x=8\times7=56\) and \(y=5\times4=20\). Therefore (x+y=76).

Step 3

Exam Tip

\(x=8\times7=56\) और \(y=5\times4=20\)। इसलिए (x+y=76) है।

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\(\frac{7!}{4!,3!}\times3!\) का मान क्या है?

What is the value of \(\frac{7!}{4!,3!}\times3!\)?

Explanation opens after your attempt
Correct Answer

C. (210)

Step 1

Concept

\(\frac{7!}{4!,3!}=35\) and (3!=6). Therefore the product is \(35\times6=210\).

Step 2

Why this answer is correct

The correct answer is C. (210). \(\frac{7!}{4!,3!}=35\) and (3!=6). Therefore the product is \(35\times6=210\).

Step 3

Exam Tip

\(\frac{7!}{4!,3!}=35\) और (3!=6)। इसलिए गुणनफल \(35\times6=210\) है।

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(\frac{(n+1)!-n!}{(n-1)!}) का सरल रूप क्या है?

What is the simplified form of (\frac{(n+1)!-n!}{(n-1)!})?

Explanation opens after your attempt
Correct Answer

A. \(n^2\)

Step 1

Concept

((n+1)!-n!=n!{(n+1)-1}=n\cdot n!). Dividing by ((n-1)!) gives \(n^2\).

Step 2

Why this answer is correct

The correct answer is A. \(n^2\). ((n+1)!-n!=n!{(n+1)-1}=n\cdot n!). Dividing by ((n-1)!) gives \(n^2\).

Step 3

Exam Tip

((n+1)!-n!=n!{(n+1)-1}=n\cdot n!)। ((n-1)!) से भाग देने पर \(n^2\) मिलता है।

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