Concept-wise Practice

arc-angle MCQ Questions for Class 11

arc-angle se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with arc-angle.

वृत्त की त्रिज्या (18) सेमी है और चाप \(15\pi\) सेमी है। केंद्र कोण डिग्री में क्या है?

The radius of a circle is (18) cm and the arc is \(15\pi\) cm. What is the central angle in degrees?

Explanation opens after your attempt
Correct Answer

C. \(150^\circ\)

Step 1

Concept

\( \theta=\frac{s}{r}=\frac{15\pi}{18}=\frac{5\pi}{6}=150^\circ \). First find the radian angle and then convert to degrees.

Step 2

Why this answer is correct

The correct answer is C. \(150^\circ\). \( \theta=\frac{s}{r}=\frac{15\pi}{18}=\frac{5\pi}{6}=150^\circ \). First find the radian angle and then convert to degrees.

Step 3

Exam Tip

\( \theta=\frac{s}{r}=\frac{15\pi}{18}=\frac{5\pi}{6}=150^\circ \) है। पहले रेडियन कोण निकालकर डिग्री में बदलें।

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यदि वृत्त की त्रिज्या (21) सेमी और चाप \(14\pi\) सेमी है तो केंद्र कोण रेडियन में क्या है?

If the radius of a circle is (21) cm and the arc is \(14\pi\) cm, what is the central angle in radians?

Explanation opens after your attempt
Correct Answer

B. \( \frac{2\pi}{3} \) रेडियन\( \frac{2\pi}{3} \) radians

Step 1

Concept

\( \theta=\frac{s}{r}=\frac{14\pi}{21}=\frac{2\pi}{3} \). Use \( \theta=\frac{s}{r} \) to find the angle from arc length.

Step 2

Why this answer is correct

The correct answer is B. \( \frac{2\pi}{3} \) रेडियन / \( \frac{2\pi}{3} \) radians. \( \theta=\frac{s}{r}=\frac{14\pi}{21}=\frac{2\pi}{3} \). Use \( \theta=\frac{s}{r} \) to find the angle from arc length.

Step 3

Exam Tip

\( \theta=\frac{s}{r}=\frac{14\pi}{21}=\frac{2\pi}{3} \) है। चाप लंबाई से कोण निकालते समय \( \theta=\frac{s}{r} \) लगाएं।

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एक वृत्त में त्रिज्या (18) सेमी और चाप \(6\pi\) सेमी है। केंद्र कोण डिग्री में क्या होगा?

In a circle the radius is (18) cm and arc is \(6\pi\) cm. What is the central angle in degrees?

Explanation opens after your attempt
Correct Answer

B. \(60^\circ\)

Step 1

Concept

\( \theta=\frac{s}{r}=\frac{6\pi}{18}=\frac{\pi}{3}=60^\circ \). First find the radian angle and then convert it into degrees.

Step 2

Why this answer is correct

The correct answer is B. \(60^\circ\). \( \theta=\frac{s}{r}=\frac{6\pi}{18}=\frac{\pi}{3}=60^\circ \). First find the radian angle and then convert it into degrees.

Step 3

Exam Tip

\( \theta=\frac{s}{r}=\frac{6\pi}{18}=\frac{\pi}{3}=60^\circ \) है। पहले रेडियन कोण निकालकर डिग्री में बदलें।

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यदि (r=12) सेमी और चाप \(s=6\pi\) सेमी है तो कोण \( \theta \) क्या होगा?

If (r=12) cm and arc \(s=6\pi\) cm then what is the angle \( \theta \)?

Explanation opens after your attempt
Correct Answer

D. \( \frac{\pi}{2} \) रेडियन\( \frac{\pi}{2} \) radians

Step 1

Concept

\( \theta=\frac{s}{r}=\frac{6\pi}{12}=\frac{\pi}{2} \) radians. Rearrange \(s=r\theta\) as \( \theta=\frac{s}{r} \).

Step 2

Why this answer is correct

The correct answer is D. \( \frac{\pi}{2} \) रेडियन / \( \frac{\pi}{2} \) radians. \( \theta=\frac{s}{r}=\frac{6\pi}{12}=\frac{\pi}{2} \) radians. Rearrange \(s=r\theta\) as \( \theta=\frac{s}{r} \).

Step 3

Exam Tip

\( \theta=\frac{s}{r}=\frac{6\pi}{12}=\frac{\pi}{2} \) रेडियन है। \(s=r\theta\) को \( \theta=\frac{s}{r} \) में बदलें।

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