समीकरण \(x^2+2px+p^2-1=0\) के मूलों की प्रकृति क्या है?
What is the nature of roots of \(x^2+2px+p^2-1=0\)?
Explanation opens after your attempt
Correct Answer
A. हमेशा वास्तविक और भिन्नAlways real and distinct
Concept
Here (D=(2p)2-4\(p^2-1\)=4). So for every real (p), roots are real and distinct.
Why this answer is correct
The correct answer is A. हमेशा वास्तविक और भिन्न / Always real and distinct. Here (D=(2p)2-4\(p^2-1\)=4). So for every real (p), roots are real and distinct.
Exam Tip
यहाँ (D=(2p)2-4\(p^2-1\)=4) है। इसलिए हर वास्तविक (p) के लिए मूल वास्तविक और भिन्न हैं।
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