वर्गमूल सर्पिल में यदि \(OP_k=\sqrt{k+1}\), तो \(\sqrt{21}\) किस (k) पर मिलेगा?
In the square root spiral, if \(OP_k=\sqrt{k+1}\), for which (k) will \(\sqrt{21}\) be obtained?
Explanation opens after your attempt
Correct Answer
C. (20)
Concept
From \(\sqrt{k+1}=\sqrt{21}\), we get (k+1=21), so (k=20). In such questions, equate the numbers under the roots.
Why this answer is correct
The correct answer is C. (20). From \(\sqrt{k+1}=\sqrt{21}\), we get (k+1=21), so (k=20). In such questions, equate the numbers under the roots.
Exam Tip
\(\sqrt{k+1}=\sqrt{21}\) से (k+1=21), इसलिए (k=20)। ऐसे प्रश्नों में वर्गमूल हटाकर अंदर की संख्याएं बराबर करें।
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