Concept-wise Practice

advanced_expression MCQ Questions for Class 10

advanced_expression se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with advanced_expression.

यदि \(\alpha,\beta\) समीकरण \(x^2+x-1=0\) की जड़ें हैं, तो \(\alpha^5+\beta^5\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2+x-1=0\), what is \(\alpha^5+\beta^5\)?

Explanation opens after your attempt
Correct Answer

A. (-11)

Step 1

Concept

Here \(\alpha+\beta=-1\) and \(\alpha\beta=-1\). The power sums give \(S_1=-1\), \(S_2=3\), \(S_3=-4\), \(S_4=7\), \(S_5=-11\).

Step 2

Why this answer is correct

The correct answer is A. (-11). Here \(\alpha+\beta=-1\) and \(\alpha\beta=-1\). The power sums give \(S_1=-1\), \(S_2=3\), \(S_3=-4\), \(S_4=7\), \(S_5=-11\).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=-1\) और \(\alpha\beta=-1\) है। शक्ति योग क्रम से \(S_1=-1\), \(S_2=3\), \(S_3=-4\), \(S_4=7\), \(S_5=-11\) मिलता है।

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यदि \(x^2-8x+15=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-8x+15=0\), what is the value of \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{34}{15}\)

Step 1

Concept

Here \(\alpha+\beta=8\) and \(\alpha\beta=15\). The value is (\frac{\(\alpha+\beta\)2-2\alpha\beta}{\alpha\beta}=\frac{34}{15}).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{34}{15}\). Here \(\alpha+\beta=8\) and \(\alpha\beta=15\). The value is (\frac{\(\alpha+\beta\)2-2\alpha\beta}{\alpha\beta}=\frac{34}{15}).

Step 3

Exam Tip

यहां \(\alpha+\beta=8\) और \(\alpha\beta=15\) है। मान (\frac{\(\alpha+\beta\)2-2\alpha\beta}{\alpha\beta}=\frac{34}{15}) होगा।

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यदि \(x^2-7x+12=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-7x+12=0\), what is the value of \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{25}{12}\)

Step 1

Concept

Here \(\alpha+\beta=7\) and \(\alpha\beta=12\). (\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\(\alpha+\beta\)2-2\alpha\beta}{\alpha\beta}=\frac{25}{12}).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{25}{12}\). Here \(\alpha+\beta=7\) and \(\alpha\beta=12\). (\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\(\alpha+\beta\)2-2\alpha\beta}{\alpha\beta}=\frac{25}{12}).

Step 3

Exam Tip

यहां \(\alpha+\beta=7\) और \(\alpha\beta=12\) है। (\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\(\alpha+\beta\)2-2\alpha\beta}{\alpha\beta}=\frac{25}{12}) होगा।

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