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4 results found for "number_of_roots" in Class 10.

Question Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

एक द्विघात समीकरण के अधिकतम कितने मूल हो सकते हैं?

What is the maximum number of roots of a quadratic equation?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

A quadratic equation has degree (2), so it can have at most (2) roots. Remember degree and maximum number of roots together.

Step 2

Why this answer is correct

The correct answer is B. (2). A quadratic equation has degree (2), so it can have at most (2) roots. Remember degree and maximum number of roots together.

Step 3

Exam Tip

द्विघात समीकरण की घात (2) होती है इसलिए अधिकतम (2) मूल हो सकते हैं। घात और अधिकतम मूल की संख्या को जोड़कर याद रखें।

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Question Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

समीकरण \(x^2+36=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+36=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

For a real number, \(x^2\ge0\). Therefore \(x^2+36=0\) has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). For a real number, \(x^2\ge0\). Therefore \(x^2+36=0\) has no real root.

Step 3

Exam Tip

वास्तविक संख्या के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+36=0\) का कोई वास्तविक मूल नहीं है।

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Question Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2+16=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+16=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

For a real number, \(x^2\ge0\). Therefore \(x^2+16=0\) has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). For a real number, \(x^2\ge0\). Therefore \(x^2+16=0\) has no real root.

Step 3

Exam Tip

वास्तविक संख्या के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+16=0\) का कोई वास्तविक मूल नहीं है।

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Question Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2+4=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+4=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Step 3

Exam Tip

क्योंकि \(x^2\ge 0\) होता है इसलिए \(x^2+4\) कभी (0) नहीं बनता। इसलिए कोई वास्तविक मूल नहीं है।

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