\(\frac{1}{2^2\cdot 5^2\cdot 9}\) के बारे में सही कथन कौन-सा है?
Which statement is correct about \(\frac{1}{2^2\cdot 5^2\cdot 9}\)?
Explanation opens after your attempt
B. असांत आवर्ती और (2) अनावर्ती आरंभिक अंकNon-terminating recurring with (2) initial non-repeating digits
Concept
Since \(9=3^2\) remains, the decimal is non-terminating recurring. The larger exponent in \(2^2\cdot 5^2\) gives (2) initial non-repeating digits.
Why this answer is correct
The correct answer is B. असांत आवर्ती और (2) अनावर्ती आरंभिक अंक / Non-terminating recurring with (2) initial non-repeating digits. Since \(9=3^2\) remains, the decimal is non-terminating recurring. The larger exponent in \(2^2\cdot 5^2\) gives (2) initial non-repeating digits.
Exam Tip
\(9=3^2\) बचता है, इसलिए दशमलव असांत आवर्ती होगा। \(2^2\cdot 5^2\) की बड़ी घात (2) आरंभिक अनावर्ती भाग दिखाती है।
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