कौन-सा विकल्प \(\sqrt{2}+\sqrt{8}+\sqrt{32}+\sqrt{128}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{2}+\sqrt{8}+\sqrt{32}+\sqrt{128}\)?
Explanation opens after your attempt
Correct Answer
A. \(15\sqrt{2}\)
Concept
\(\sqrt{8}=2\sqrt{2}\), \(\sqrt{32}=4\sqrt{2}\), and \(\sqrt{128}=8\sqrt{2}\).
Why this answer is correct
The sum is ((1+2+4+8)\sqrt{2}=15\sqrt{2}).
Exam Tip
Recognize the pattern of perfect-square factors. चरण 1: \(\sqrt{8}=2\sqrt{2}\), \(\sqrt{32}=4\sqrt{2}\), और \(\sqrt{128}=8\sqrt{2}\)। चरण 2: योग ((1+2+4+8)\sqrt{2}=15\sqrt{2}) है। चरण 3: गुणनखंडों में पूर्ण वर्गों का क्रम पहचानें।
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