कौन-सा विकल्प \(\frac{3}{2+\sqrt{5}}\) का परिमेय हर वाला रूप है?
Which option is the rationalized form of \(\frac{3}{2+\sqrt{5}}\)?
Explanation opens after your attempt
Correct Answer
B. (3\(\sqrt{5}-2\))
Concept
The conjugate of the denominator is \(2-\sqrt{5}\).
Why this answer is correct
(\frac{3}{2+\sqrt{5}}\times\frac{2-\sqrt{5}}{2-\sqrt{5}}=\frac{3\(2-\sqrt{5}\)}{4-5}=3\(\sqrt{5}-2\)).
Exam Tip
Use the difference of squares in the denominator when multiplying by a conjugate. चरण 1: हर का संयुग्मी \(2-\sqrt{5}\) है। चरण 2: (\frac{3}{2+\sqrt{5}}\times\frac{2-\sqrt{5}}{2-\sqrt{5}}=\frac{3\(2-\sqrt{5}\)}{4-5}=3\(\sqrt{5}-2\))। चरण 3: संयुग्मी से गुणा करते समय हर में अंतर के वर्ग का प्रयोग करें।
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