Expert Mathematics Real Numbers Class 10 Level 20

\(0.\overline{045}\) का सरलतम भिन्न रूप कौन-सा है?

Which is the lowest fraction form of \(0.\overline{045}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{5}{111}\)

Step 1

Concept

\(0.\overline{045}=\frac{45}{999}\), and reducing by (9) gives \(\frac{5}{111}\). First form the denominator with (9)'s according to the repeating digits.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{5}{111}\). \(0.\overline{045}=\frac{45}{999}\), and reducing by (9) gives \(\frac{5}{111}\). First form the denominator with (9)'s according to the repeating digits.

Step 3

Exam Tip

\(0.\overline{045}=\frac{45}{999}\) और (9) से सरल करने पर \(\frac{5}{111}\) मिलता है। आवर्ती अंकों की संख्या के अनुसार पहले (9) वाला हर बनाएं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(0.\overline{045}\) का सरलतम भिन्न रूप कौन-सा है? / Which is the lowest fraction form of \(0.\overline{045}\)?

Correct Answer: A. \(\frac{5}{111}\). Explanation: \(0.\overline{045}=\frac{45}{999}\) और (9) से सरल करने पर \(\frac{5}{111}\) मिलता है। आवर्ती अंकों की संख्या के अनुसार पहले (9) वाला हर बनाएं। / \(0.\overline{045}=\frac{45}{999}\), and reducing by (9) gives \(\frac{5}{111}\). First form the denominator with (9)'s according to the repeating digits.

Which concept should I revise for this Mathematics MCQ?

\(0.\overline{045}=\frac{45}{999}\), and reducing by (9) gives \(\frac{5}{111}\). First form the denominator with (9)'s according to the repeating digits.

What exam hint can help solve this Mathematics question?

\(0.\overline{045}=\frac{45}{999}\) और (9) से सरल करने पर \(\frac{5}{111}\) मिलता है। आवर्ती अंकों की संख्या के अनुसार पहले (9) वाला हर बनाएं।

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