Expert Mathematics Real Numbers Class 10 Level 21

\(\frac{2^5\cdot 17}{2^9\cdot 5^2\cdot 17^2}\) का दशमलव प्रसार कैसा होगा?

What type of decimal expansion will \(\frac{2^5\cdot 17}{2^9\cdot 5^2\cdot 17^2}\) have?

Explanation opens after your attempt
Correct Answer

B. असांत आवर्तीNon-terminating recurring

Step 1

Concept

After cancellation, the denominator becomes \(2^4\cdot 5^2\cdot 17\). Since (17) remains, the decimal is non-terminating recurring.

Step 2

Why this answer is correct

The correct answer is B. असांत आवर्ती / Non-terminating recurring. After cancellation, the denominator becomes \(2^4\cdot 5^2\cdot 17\). Since (17) remains, the decimal is non-terminating recurring.

Step 3

Exam Tip

कटौती के बाद हर \(2^4\cdot 5^2\cdot 17\) बचेगा। (17) बचने से दशमलव असांत आवर्ती होगा।

FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{2^5\cdot 17}{2^9\cdot 5^2\cdot 17^2}\) का दशमलव प्रसार कैसा होगा? / What type of decimal expansion will \(\frac{2^5\cdot 17}{2^9\cdot 5^2\cdot 17^2}\) have?

Correct Answer: B. असांत आवर्ती / Non-terminating recurring. Explanation: कटौती के बाद हर \(2^4\cdot 5^2\cdot 17\) बचेगा। (17) बचने से दशमलव असांत आवर्ती होगा। / After cancellation, the denominator becomes \(2^4\cdot 5^2\cdot 17\). Since (17) remains, the decimal is non-terminating recurring.

Which concept should I revise for this Mathematics MCQ?

After cancellation, the denominator becomes \(2^4\cdot 5^2\cdot 17\). Since (17) remains, the decimal is non-terminating recurring.

What exam hint can help solve this Mathematics question?

कटौती के बाद हर \(2^4\cdot 5^2\cdot 17\) बचेगा। (17) बचने से दशमलव असांत आवर्ती होगा।

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