Expert Mathematics Polynomials Class 10 Level 27

\(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}\) का सरलतम परिमेयकृत रूप क्या है?

What is the simplest rationalized form of \(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}\)?

Explanation opens after your attempt
Correct Answer

A. \(4-\sqrt{15}\)

Step 1

Concept

Multiplying by the conjugate gives \(\frac{8-2\sqrt{15}}{2}=4-\sqrt{15}\). In exams simplify the fraction at the end.

Step 2

Why this answer is correct

The correct answer is A. \(4-\sqrt{15}\). Multiplying by the conjugate gives \(\frac{8-2\sqrt{15}}{2}=4-\sqrt{15}\). In exams simplify the fraction at the end.

Step 3

Exam Tip

हर के संयुग्मी से गुणा करने पर \(\frac{8-2\sqrt{15}}{2}=4-\sqrt{15}\) मिलता है। परीक्षा में अंत में भिन्न को सरल करें।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}\) का सरलतम परिमेयकृत रूप क्या है? / What is the simplest rationalized form of \(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}\)?

Correct Answer: A. \(4-\sqrt{15}\). Explanation: हर के संयुग्मी से गुणा करने पर \(\frac{8-2\sqrt{15}}{2}=4-\sqrt{15}\) मिलता है। परीक्षा में अंत में भिन्न को सरल करें। / Multiplying by the conjugate gives \(\frac{8-2\sqrt{15}}{2}=4-\sqrt{15}\). In exams simplify the fraction at the end.

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate gives \(\frac{8-2\sqrt{15}}{2}=4-\sqrt{15}\). In exams simplify the fraction at the end.

What exam hint can help solve this Mathematics question?

हर के संयुग्मी से गुणा करने पर \(\frac{8-2\sqrt{15}}{2}=4-\sqrt{15}\) मिलता है। परीक्षा में अंत में भिन्न को सरल करें।

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