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What is the form of (\frac{1}{3... | 5: Irrational numb...
\(\frac{1}{3+\sqrt{8}}\) का परिमेय हर वाला रूप क्या है?
What is the form of \(\frac{1}{3+\sqrt{8}}\) with a rational denominator?
#real-numbers
#rationalisation
#conjugate
A \(3-\sqrt{8}\)
B \(3+\sqrt{8}\)
C \(\frac{3-\sqrt{8}}{17}\)
D \(\sqrt{8}-3\)
Explanation opens after your attempt
Correct Answer
A. \(3-\sqrt{8}\)
Step 1
Concept
The conjugate of \(3+\sqrt{8}\) is \(3-\sqrt{8}\).
Step 2
Why this answer is correct
\(\frac{1}{3+\sqrt{8}}\times\frac{3-\sqrt{8}}{3-\sqrt{8}}=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\).
Step 3
Exam Tip
Use the conjugate of the denominator for rationalisation. चरण 1: हर \(3+\sqrt{8}\) का संयुग्म \(3-\sqrt{8}\) है। चरण 2: \(\frac{1}{3+\sqrt{8}}\times\frac{3-\sqrt{8}}{3-\sqrt{8}}=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\)। चरण 3: परिमेयकरण में हर का संयुग्म प्रयोग करें।
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