\(6x^2+11x+3=0\) में मध्य पद का सही विभाजन कौनसा है?
What is the correct splitting of the middle term in \(6x^2+11x+3=0\)?
Explanation opens after your attempt
A. \(6x^2+9x+2x+3=0\)
Concept
Here (ac=18) and (9+2=11), so (11x) is split as (9x+2x). In exams, check both sum (b) and product (ac).
Why this answer is correct
The correct answer is A. \(6x^2+9x+2x+3=0\). Here (ac=18) and (9+2=11), so (11x) is split as (9x+2x). In exams, check both sum (b) and product (ac).
Exam Tip
यहां (ac=18) और (9+2=11), इसलिए (11x) को (9x+2x) में तोड़ते हैं। परीक्षा में योग (b) और गुणनफल (ac) दोनों जांचें।
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