समीकरण \(5x^2-4x+t=0\) के वास्तविक और समान मूलों के लिए (t) क्या होगा?
What is (t) for real and equal roots of \(5x^2-4x+t=0\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{4}{5}\)
Concept
(D=(-4)2-4(5)t=0) gives \(t=\frac{4}{5}\). Always set (D=0) for equal roots.
Why this answer is correct
The correct answer is A. \(\frac{4}{5}\). (D=(-4)2-4(5)t=0) gives \(t=\frac{4}{5}\). Always set (D=0) for equal roots.
Exam Tip
(D=(-4)2-4(5)t=0) से \(t=\frac{4}{5}\) मिलता है। समान मूलों के लिए हमेशा (D=0) रखें।
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