\(24x^2-50x+25=0\) में मध्य पद का सही विभाजन कौनसा है?
What is the correct splitting of the middle term in \(24x^2-50x+25=0\)?
Explanation opens after your attempt
Correct Answer
A. \(24x^2-30x-20x+25=0\)
Concept
Here (ac=600) and (-30+(-20)=-50), so the correct split is (-30x-20x). In exams, even for large (ac), match both sum and product.
Why this answer is correct
The correct answer is A. \(24x^2-30x-20x+25=0\). Here (ac=600) and (-30+(-20)=-50), so the correct split is (-30x-20x). In exams, even for large (ac), match both sum and product.
Exam Tip
यहां (ac=600) और (-30+(-20)=-50), इसलिए सही विभाजन (-30x-20x) है। परीक्षा में बड़ा (ac) हो तो भी योग और गुणनफल दोनों मिलाएं।
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