\(10x^2-17x+3=0\) में मध्य पद का सही विभाजन कौनसा है?
What is the correct splitting of the middle term in \(10x^2-17x+3=0\)?
Explanation opens after your attempt
A. \(10x^2-15x-2x+3=0\)
Concept
Here (ac=30) and (-15+(-2)=-17), so the middle term is (-15x-2x). In exams, check both sum and product.
Why this answer is correct
The correct answer is A. \(10x^2-15x-2x+3=0\). Here (ac=30) and (-15+(-2)=-17), so the middle term is (-15x-2x). In exams, check both sum and product.
Exam Tip
यहां (ac=30) और (-15+(-2)=-17), इसलिए मध्य पद (-15x-2x) होगा। परीक्षा में योग और गुणनफल दोनों जांचें।
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