Easy Mathematics Chapter 1: Real Numbers Class 10 Level 16

\(\sqrt{5}\) को अपरिमेय सिद्ध करने की शुरुआत में क्या माना जाता है?

What is assumed at the beginning to prove that \(\sqrt{5}\) is irrational?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{5}\) परिमेय है और \(\sqrt{5}=\frac{p}{q}\), जहां (p) और (q) सहअभाज्य हैं\(\sqrt{5}\) is rational and \(\sqrt{5}=\frac{p}{q}\), where (p) and (q) are coprime

Step 1

Concept

In the contradiction method, we assume the opposite.

Step 2

Why this answer is correct

So \(\sqrt{5}\) is assumed rational and written as \(\frac{p}{q}\).

Step 3

Exam Tip

Do not forget to mention that (p) and (q) are coprime. चरण 1: विरोधाभास विधि में उलटी बात मानते हैं। चरण 2: इसलिए \(\sqrt{5}\) को परिमेय मानकर \(\frac{p}{q}\) के रूप में लिखा जाता है। चरण 3: (p) और (q) को सहअभाज्य लिखना न भूलें।

FAQs

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The correct answer is A. \(\sqrt{5}\) परिमेय है और \(\sqrt{5}=\frac{p}{q}\), जहां (p) और (q) सहअभाज्य हैं / \(\sqrt{5}\) is rational and \(\sqrt{5}=\frac{p}{q}\), where (p) and (q) are coprime.

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