(x-2-(s+t)x+st=0) के मूल कौनसे हैं?
What are the roots of (x-2-(s+t)x+st=0)?
Explanation opens after your attempt
A. (x=s,t)
Concept
The equation is equivalent to ((x-s)(x-t)=0), so the roots are (s) and (t). In exams, apply zero product rule to symbolic factors too.
Why this answer is correct
The correct answer is A. (x=s,t). The equation is equivalent to ((x-s)(x-t)=0), so the roots are (s) and (t). In exams, apply zero product rule to symbolic factors too.
Exam Tip
यह समीकरण ((x-s)(x-t)=0) के बराबर है, इसलिए मूल (s) और (t) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी शून्य गुणनफल नियम लगाएं।
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