Expert Mathematics Quadratic Equations Class 10 Level 34

(x-2-(r+t)x+rt=0) के मूल कौनसे हैं?

What are the roots of (x-2-(r+t)x+rt=0)?

Explanation opens after your attempt
Correct Answer

A. (x=r,t)

Step 1

Concept

The equation is equivalent to ((x-r)(x-t)=0), so the roots are (r) and (t). In exams, apply zero product rule to symbolic factors too.

Step 2

Why this answer is correct

The correct answer is A. (x=r,t). The equation is equivalent to ((x-r)(x-t)=0), so the roots are (r) and (t). In exams, apply zero product rule to symbolic factors too.

Step 3

Exam Tip

यह समीकरण ((x-r)(x-t)=0) के बराबर है, इसलिए मूल (r) और (t) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी शून्य गुणनफल नियम लगाएं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

(x-2-(r+t)x+rt=0) के मूल कौनसे हैं? / What are the roots of (x-2-(r+t)x+rt=0)?

Correct Answer: A. (x=r,t). Explanation: यह समीकरण ((x-r)(x-t)=0) के बराबर है, इसलिए मूल (r) और (t) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी शून्य गुणनफल नियम लगाएं। / The equation is equivalent to ((x-r)(x-t)=0), so the roots are (r) and (t). In exams, apply zero product rule to symbolic factors too.

Which concept should I revise for this Mathematics MCQ?

The equation is equivalent to ((x-r)(x-t)=0), so the roots are (r) and (t). In exams, apply zero product rule to symbolic factors too.

What exam hint can help solve this Mathematics question?

यह समीकरण ((x-r)(x-t)=0) के बराबर है, इसलिए मूल (r) और (t) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी शून्य गुणनफल नियम लगाएं।

Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.