\(x^4-5x^2+4=0\) के वास्तविक हल कौनसे हैं?
What are the real solutions of \(x^4-5x^2+4=0\)?
Explanation opens after your attempt
A. \(x=\pm1,\pm2\)
Concept
From \(y^2-5y+4=0\), (y=1,4), so \(x^2=1,4\) and \(x=\pm1,\pm2\). In exams, do not forget to return to (x).
Why this answer is correct
The correct answer is A. \(x=\pm1,\pm2\). From \(y^2-5y+4=0\), (y=1,4), so \(x^2=1,4\) and \(x=\pm1,\pm2\). In exams, do not forget to return to (x).
Exam Tip
\(y^2-5y+4=0\) से (y=1,4), इसलिए \(x^2=1,4\) और \(x=\pm1,\pm2\) हैं। परीक्षा में वापस (x) के मान निकालना न भूलें।
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