Expert Mathematics Chapter 1: Real Numbers Class 10 Level 10

तीन संख्याओं के अभाज्य गुणनखंड \(2^3\times3^2\times11\), \(2^5\times3\times5\) और \(2^2\times3^4\times7\) हैं। इनका लघुत्तम समापवर्त्य क्या होगा?

The prime factorisations of three numbers are \(2^3\times3^2\times11\), \(2^5\times3\times5\), and \(2^2\times3^4\times7\). What will be their LCM?

Explanation opens after your attempt
Correct Answer

A. \(2^5\times3^4\times5\times7\times11\)

Step 1

Concept

LCM uses the highest power of every prime factor present.

Step 2

Why this answer is correct

The highest powers are \(2^5\), \(3^4\), (5), (7), and (11).

Step 3

Exam Tip

Include a prime even if it appears in only one number. चरण 1: लघुत्तम समापवर्त्य में सभी अभाज्य गुणनखंडों की सबसे बड़ी घात ली जाती है। चरण 2: यहाँ बड़ी घातें \(2^5\), \(3^4\), (5), (7) और (11) हैं। चरण 3: जो अभाज्य केवल एक संख्या में हो, उसे भी लघुत्तम समापवर्त्य में अवश्य रखें।

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What is the correct answer to this Mathematics MCQ?

The correct answer is A. \(2^5\times3^4\times5\times7\times11\).

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