किस विकल्प में अपरिमेय संख्या को परिमेय संख्या में बदलने के लिए सही संयुग्मी चुना गया है?
In which option is the correct conjugate chosen to rationalize an irrational denominator?
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{5+\sqrt{2}}\) के लिए \(5-\sqrt{2}\)For \(\frac{1}{5+\sqrt{2}}\) use \(5-\sqrt{2}\)
Concept
The conjugate of \(5+\sqrt{2}\) is \(5-\sqrt{2}\). In exams changing the middle sign is the key idea of a conjugate.
Why this answer is correct
The correct answer is A. \(\frac{1}{5+\sqrt{2}}\) के लिए \(5-\sqrt{2}\) / For \(\frac{1}{5+\sqrt{2}}\) use \(5-\sqrt{2}\). The conjugate of \(5+\sqrt{2}\) is \(5-\sqrt{2}\). In exams changing the middle sign is the key idea of a conjugate.
Exam Tip
\(5+\sqrt{2}\) का संयुग्मी \(5-\sqrt{2}\) है। परीक्षा में बीच का चिन्ह बदलना ही संयुग्मी बनाने की मुख्य बात है।
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