\(\frac{1}{2^3\cdot 5^4\cdot 19^2}\) के दशमलव में आवर्ती भाग से पहले कितने अनावर्ती अंक आएँगे?
In the decimal expansion of \(\frac{1}{2^3\cdot 5^4\cdot 19^2}\), how many non-repeating digits appear before the recurring part?
Explanation opens after your attempt
Correct Answer
B. (4)
Concept
Since \(19^2\) remains, the decimal is non-terminating recurring, and the larger exponent among (2) and (5) is (4). In such questions, separate recurrence from the initial delay.
Why this answer is correct
The correct answer is B. (4). Since \(19^2\) remains, the decimal is non-terminating recurring, and the larger exponent among (2) and (5) is (4). In such questions, separate recurrence from the initial delay.
Exam Tip
\(19^2\) बचने से दशमलव असांत आवर्ती होगा और (2), (5) की बड़ी घात (4) आरंभिक अनावर्ती भाग देगी। ऐसे प्रश्न में आवर्तीपन और आरंभिक देरी अलग-अलग देखें।
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