Expert Mathematics Polynomials Class 10 Level 27

यदि \(x=\sqrt{7}+\sqrt{5}\), तो \(x^2\) का सही मान क्या है?

If \(x=\sqrt{7}+\sqrt{5}\), what is the correct value of \(x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(12+2\sqrt{35}\)

Step 1

Concept

\(x^2=7+5+2\sqrt{35}=12+2\sqrt{35}\). In exams do not miss (2ab) in ((a+b)2).

Step 2

Why this answer is correct

The correct answer is A. \(12+2\sqrt{35}\). \(x^2=7+5+2\sqrt{35}=12+2\sqrt{35}\). In exams do not miss (2ab) in ((a+b)2).

Step 3

Exam Tip

\(x^2=7+5+2\sqrt{35}=12+2\sqrt{35}\) है। परीक्षा में ((a+b)2) में (2ab) न छोड़ें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{7}+\sqrt{5}\), तो \(x^2\) का सही मान क्या है? / If \(x=\sqrt{7}+\sqrt{5}\), what is the correct value of \(x^2\)?

Correct Answer: A. \(12+2\sqrt{35}\). Explanation: \(x^2=7+5+2\sqrt{35}=12+2\sqrt{35}\) है। परीक्षा में ((a+b)2) में (2ab) न छोड़ें। / \(x^2=7+5+2\sqrt{35}=12+2\sqrt{35}\). In exams do not miss (2ab) in ((a+b)2).

Which concept should I revise for this Mathematics MCQ?

\(x^2=7+5+2\sqrt{35}=12+2\sqrt{35}\). In exams do not miss (2ab) in ((a+b)2).

What exam hint can help solve this Mathematics question?

\(x^2=7+5+2\sqrt{35}=12+2\sqrt{35}\) है। परीक्षा में ((a+b)2) में (2ab) न छोड़ें।

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