Expert Mathematics Polynomials Class 10 Level 26

यदि \(x=\sqrt{7}-\sqrt{3}\), तो \(x^2\) क्या है?

If \(x=\sqrt{7}-\sqrt{3}\), what is \(x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(10-2\sqrt{21}\)

Step 1

Concept

\(x^2=7+3-2\sqrt{21}=10-2\sqrt{21}\). In exams apply ((a-b)2=a-2+b-2-2ab).

Step 2

Why this answer is correct

The correct answer is A. \(10-2\sqrt{21}\). \(x^2=7+3-2\sqrt{21}=10-2\sqrt{21}\). In exams apply ((a-b)2=a-2+b-2-2ab).

Step 3

Exam Tip

\(x^2=7+3-2\sqrt{21}=10-2\sqrt{21}\) है। परीक्षा में ((a-b)2=a-2+b-2-2ab) लगाएं।

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{7}-\sqrt{3}\), तो \(x^2\) क्या है? / If \(x=\sqrt{7}-\sqrt{3}\), what is \(x^2\)?

Correct Answer: A. \(10-2\sqrt{21}\). Explanation: \(x^2=7+3-2\sqrt{21}=10-2\sqrt{21}\) है। परीक्षा में ((a-b)2=a-2+b-2-2ab) लगाएं। / \(x^2=7+3-2\sqrt{21}=10-2\sqrt{21}\). In exams apply ((a-b)2=a-2+b-2-2ab).

Which concept should I revise for this Mathematics MCQ?

\(x^2=7+3-2\sqrt{21}=10-2\sqrt{21}\). In exams apply ((a-b)2=a-2+b-2-2ab).

What exam hint can help solve this Mathematics question?

\(x^2=7+3-2\sqrt{21}=10-2\sqrt{21}\) है। परीक्षा में ((a-b)2=a-2+b-2-2ab) लगाएं।

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