Expert Mathematics Polynomials Class 10 Level 27

यदि \(x=\sqrt{11}-\sqrt{2}\), तो \(x^2\) क्या है?

If \(x=\sqrt{11}-\sqrt{2}\), what is \(x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(13-2\sqrt{22}\)

Step 1

Concept

\(x^2=11+2-2\sqrt{22}=13-2\sqrt{22}\). In exams do not forget the middle term of ((a-b)2).

Step 2

Why this answer is correct

The correct answer is A. \(13-2\sqrt{22}\). \(x^2=11+2-2\sqrt{22}=13-2\sqrt{22}\). In exams do not forget the middle term of ((a-b)2).

Step 3

Exam Tip

\(x^2=11+2-2\sqrt{22}=13-2\sqrt{22}\) है। परीक्षा में ((a-b)2) का मध्य पद न भूलें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{11}-\sqrt{2}\), तो \(x^2\) क्या है? / If \(x=\sqrt{11}-\sqrt{2}\), what is \(x^2\)?

Correct Answer: A. \(13-2\sqrt{22}\). Explanation: \(x^2=11+2-2\sqrt{22}=13-2\sqrt{22}\) है। परीक्षा में ((a-b)2) का मध्य पद न भूलें। / \(x^2=11+2-2\sqrt{22}=13-2\sqrt{22}\). In exams do not forget the middle term of ((a-b)2).

Which concept should I revise for this Mathematics MCQ?

\(x^2=11+2-2\sqrt{22}=13-2\sqrt{22}\). In exams do not forget the middle term of ((a-b)2).

What exam hint can help solve this Mathematics question?

\(x^2=11+2-2\sqrt{22}=13-2\sqrt{22}\) है। परीक्षा में ((a-b)2) का मध्य पद न भूलें।

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