Hard Mathematics Polynomials Class 10 Level 26

यदि \(x=3-\sqrt{2}\), तो \(x^2-6x+7\) का मान क्या है?

If \(x=3-\sqrt{2}\), what is the value of \(x^2-6x+7\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Since \(x-3=-\sqrt{2}\), ((x-3)2=2), hence \(x^2-6x+7=0\). Handle \(a-\sqrt{b}\) the same way in exams.

Step 2

Why this answer is correct

The correct answer is A. (0). Since \(x-3=-\sqrt{2}\), ((x-3)2=2), hence \(x^2-6x+7=0\). Handle \(a-\sqrt{b}\) the same way in exams.

Step 3

Exam Tip

\(x-3=-\sqrt{2}\), इसलिए ((x-3)2=2) से \(x^2-6x+7=0\) है। परीक्षा में \(a-\sqrt{b}\) को भी इसी विधि से संभालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=3-\sqrt{2}\), तो \(x^2-6x+7\) का मान क्या है? / If \(x=3-\sqrt{2}\), what is the value of \(x^2-6x+7\)?

Correct Answer: A. (0). Explanation: \(x-3=-\sqrt{2}\), इसलिए ((x-3)2=2) से \(x^2-6x+7=0\) है। परीक्षा में \(a-\sqrt{b}\) को भी इसी विधि से संभालें। / Since \(x-3=-\sqrt{2}\), ((x-3)2=2), hence \(x^2-6x+7=0\). Handle \(a-\sqrt{b}\) the same way in exams.

Which concept should I revise for this Mathematics MCQ?

Since \(x-3=-\sqrt{2}\), ((x-3)2=2), hence \(x^2-6x+7=0\). Handle \(a-\sqrt{b}\) the same way in exams.

What exam hint can help solve this Mathematics question?

\(x-3=-\sqrt{2}\), इसलिए ((x-3)2=2) से \(x^2-6x+7=0\) है। परीक्षा में \(a-\sqrt{b}\) को भी इसी विधि से संभालें।

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