यदि \(x^2-14x+33=0\) के मूल \(\alpha,\beta\) हैं, तो नए मूल \(\alpha+5,\beta+5\) वाला समीकरण कौनसा है?
If roots of \(x^2-14x+33=0\) are \(\alpha,\beta\), which equation has roots \(\alpha+5,\beta+5\)?
Explanation opens after your attempt
Correct Answer
A. \(x^2-24x+128=0\)
Concept
The roots are (3,11), so new roots are (8,16), and the equation is ((x-8)(x-16)=0). In exams, form the new roots and then the new equation.
Why this answer is correct
The correct answer is A. \(x^2-24x+128=0\). The roots are (3,11), so new roots are (8,16), and the equation is ((x-8)(x-16)=0). In exams, form the new roots and then the new equation.
Exam Tip
मूल (3,11) हैं, इसलिए नए मूल (8,16) होंगे और समीकरण ((x-8)(x-16)=0) है। परीक्षा में नए मूल बनाकर नया समीकरण लिखें।
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