यदि \(x^2-12x+20=0\) के मूल \(\alpha,\beta\) हैं, तो नए मूल \(\alpha+4,\beta+4\) वाला समीकरण कौनसा है?
If roots of \(x^2-12x+20=0\) are \(\alpha,\beta\), which equation has roots \(\alpha+4,\beta+4\)?
Explanation opens after your attempt
Correct Answer
A. \(x^2-20x+84=0\)
Concept
The roots are (2,10), so new roots are (6,14), and the equation is ((x-6)(x-14)=0). In exams, form the new roots and then the new equation.
Why this answer is correct
The correct answer is A. \(x^2-20x+84=0\). The roots are (2,10), so new roots are (6,14), and the equation is ((x-6)(x-14)=0). In exams, form the new roots and then the new equation.
Exam Tip
मूल (2,10) हैं, इसलिए नए मूल (6,14) होंगे और समीकरण ((x-6)(x-14)=0) है। परीक्षा में नए मूल बनाकर नया समीकरण लिखें।
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