यदि (p(x)=x-2-5x+6) है, तो (p\(\sqrt{2}\)) किस प्रकार की संख्या है?
If (p(x)=x-2-5x+6), what type of number is (p\(\sqrt{2}\))?
Explanation opens after your attempt
Correct Answer
B. अपरिमेयIrrational
Concept
(p\(\sqrt{2}\)=2-5\sqrt{2}+6=8-5\sqrt{2}), which is irrational. In exams substitute first and then simplify the radical.
Why this answer is correct
The correct answer is B. अपरिमेय / Irrational. (p\(\sqrt{2}\)=2-5\sqrt{2}+6=8-5\sqrt{2}), which is irrational. In exams substitute first and then simplify the radical.
Exam Tip
(p\(\sqrt{2}\)=2-5\sqrt{2}+6=8-5\sqrt{2}), जो अपरिमेय है। परीक्षा में पहले प्रतिस्थापन करें फिर वर्गमूल को सरल करें।
Login to save your score, XP, coins and progress.