यदि (p(x)=x-2-2x-8) है तो ग्राफ (x)-अक्ष को किन बिंदुओं पर मिलेगा?
If (p(x)=x-2-2x-8), at which points will the graph meet the (x)-axis?
Explanation opens after your attempt
A. ((-2,0)) और ((4,0))((-2,0)) and ((4,0))
Concept
(x-2-2x-8=(x-4)(x+2)). So the graph meets the (x)-axis at (x=4) and (x=-2).
Why this answer is correct
The correct answer is A. ((-2,0)) और ((4,0)) / ((-2,0)) and ((4,0)). (x-2-2x-8=(x-4)(x+2)). So the graph meets the (x)-axis at (x=4) and (x=-2).
Exam Tip
(x-2-2x-8=(x-4)(x+2)) है। अतः (x=4) और (x=-2) पर ग्राफ (x)-अक्ष से मिलेगा।
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