Expert Mathematics Polynomials Class 10 Level 27

यदि (p(x)=x-2-14x+38), तो शून्यकों का सही प्रकार क्या है?

If (p(x)=x-2-14x+38), what is the correct type of its zeroes?

Explanation opens after your attempt
Correct Answer

A. वास्तविक अपरिमेयReal irrational

Step 1

Concept

The discriminant is (196-152=44) and \(\sqrt{44}\) is irrational. Hence the zeroes are real irrational.

Step 2

Why this answer is correct

The correct answer is A. वास्तविक अपरिमेय / Real irrational. The discriminant is (196-152=44) and \(\sqrt{44}\) is irrational. Hence the zeroes are real irrational.

Step 3

Exam Tip

विविक्तकर (196-152=44) है और \(\sqrt{44}\) अपरिमेय है। इसलिए शून्यक वास्तविक अपरिमेय हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-14x+38), तो शून्यकों का सही प्रकार क्या है? / If (p(x)=x-2-14x+38), what is the correct type of its zeroes?

Correct Answer: A. वास्तविक अपरिमेय / Real irrational. Explanation: विविक्तकर (196-152=44) है और \(\sqrt{44}\) अपरिमेय है। इसलिए शून्यक वास्तविक अपरिमेय हैं। / The discriminant is (196-152=44) and \(\sqrt{44}\) is irrational. Hence the zeroes are real irrational.

Which concept should I revise for this Mathematics MCQ?

The discriminant is (196-152=44) and \(\sqrt{44}\) is irrational. Hence the zeroes are real irrational.

What exam hint can help solve this Mathematics question?

विविक्तकर (196-152=44) है और \(\sqrt{44}\) अपरिमेय है। इसलिए शून्यक वास्तविक अपरिमेय हैं।

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