यदि (n) सबसे छोटा धनात्मक पूर्णांक है जिससे \(\frac{n}{2^4\cdot 5\cdot 7^3\cdot 11}\) का दशमलव सांत हो तो (n) क्या होगा?
If (n) is the smallest positive integer for which \(\frac{n}{2^4\cdot 5\cdot 7^3\cdot 11}\) has a terminating decimal, what is (n)?
Explanation opens after your attempt
Correct Answer
A. (3773)
Concept
The factors \(7^3\) and (11) must be removed from the reduced denominator, so \(n=7^3\cdot 11=3773\). For the least value, do not cancel (2) and (5).
Why this answer is correct
The correct answer is A. (3773). The factors \(7^3\) and (11) must be removed from the reduced denominator, so \(n=7^3\cdot 11=3773\). For the least value, do not cancel (2) and (5).
Exam Tip
सरलतम हर से \(7^3\) और (11) हटने चाहिए इसलिए \(n=7^3\cdot 11=3773\) होगा। न्यूनतम मान में (2) और (5) को काटना जरूरी नहीं है।
Login to save your score, XP, coins and progress.