Expert Mathematics Real Numbers Class 10 Level 21

\(\frac{37}{2^4\cdot 5^8}\) को \(\frac{N}{10^8}\) के रूप में लिखने पर (N) क्या होगा?

If \(\frac{37}{2^4\cdot 5^8}\) is written as \(\frac{N}{10^8}\), what is (N)?

Explanation opens after your attempt
Correct Answer

B. (592)

Step 1

Concept

Since \(10^8=2^8\cdot 5^8\), the denominator lacks \(2^4\). Thus \(N=37\cdot 16=592\).

Step 2

Why this answer is correct

The correct answer is B. (592). Since \(10^8=2^8\cdot 5^8\), the denominator lacks \(2^4\). Thus \(N=37\cdot 16=592\).

Step 3

Exam Tip

\(10^8=2^8\cdot 5^8\) है इसलिए हर में \(2^4\) की कमी है। \(N=37\cdot 16=592\) होगा।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{37}{2^4\cdot 5^8}\) को \(\frac{N}{10^8}\) के रूप में लिखने पर (N) क्या होगा? / If \(\frac{37}{2^4\cdot 5^8}\) is written as \(\frac{N}{10^8}\), what is (N)?

Correct Answer: B. (592). Explanation: \(10^8=2^8\cdot 5^8\) है इसलिए हर में \(2^4\) की कमी है। \(N=37\cdot 16=592\) होगा। / Since \(10^8=2^8\cdot 5^8\), the denominator lacks \(2^4\). Thus \(N=37\cdot 16=592\).

Which concept should I revise for this Mathematics MCQ?

Since \(10^8=2^8\cdot 5^8\), the denominator lacks \(2^4\). Thus \(N=37\cdot 16=592\).

What exam hint can help solve this Mathematics question?

\(10^8=2^8\cdot 5^8\) है इसलिए हर में \(2^4\) की कमी है। \(N=37\cdot 16=592\) होगा।

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