Expert Mathematics Quadratic Equations Class 10 Level 35

यदि \(\alpha,\beta\) समीकरण \(7x^2-25x+12=0\) के मूल हैं, तो \(\alpha\beta\) क्या है?

If \(\alpha,\beta\) are roots of \(7x^2-25x+12=0\), what is \(\alpha\beta\)?

Explanation opens after your attempt
Correct Answer

A. \( \frac{12}{7}\)

Step 1

Concept

The product of roots is \(\frac{c}{a}=\frac{12}{7}\). In exams, use \(\frac{c}{a}\) for the product.

Step 2

Why this answer is correct

The correct answer is A. \( \frac{12}{7}\). The product of roots is \(\frac{c}{a}=\frac{12}{7}\). In exams, use \(\frac{c}{a}\) for the product.

Step 3

Exam Tip

मूलों का गुणनफल \(\frac{c}{a}=\frac{12}{7}\) है। परीक्षा में गुणनफल के लिए \(\frac{c}{a}\) का प्रयोग करें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\alpha,\beta\) समीकरण \(7x^2-25x+12=0\) के मूल हैं, तो \(\alpha\beta\) क्या है? / If \(\alpha,\beta\) are roots of \(7x^2-25x+12=0\), what is \(\alpha\beta\)?

Correct Answer: A. \( \frac{12}{7}\). Explanation: मूलों का गुणनफल \(\frac{c}{a}=\frac{12}{7}\) है। परीक्षा में गुणनफल के लिए \(\frac{c}{a}\) का प्रयोग करें। / The product of roots is \(\frac{c}{a}=\frac{12}{7}\). In exams, use \(\frac{c}{a}\) for the product.

Which concept should I revise for this Mathematics MCQ?

The product of roots is \(\frac{c}{a}=\frac{12}{7}\). In exams, use \(\frac{c}{a}\) for the product.

What exam hint can help solve this Mathematics question?

मूलों का गुणनफल \(\frac{c}{a}=\frac{12}{7}\) है। परीक्षा में गुणनफल के लिए \(\frac{c}{a}\) का प्रयोग करें।

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