Expert Mathematics Polynomials Class 10 Level 27

यदि \(\alpha=5+2\sqrt{6}\) और \(\beta=5-2\sqrt{6}\), तो \(\alpha\beta\) क्या है?

If \(\alpha=5+2\sqrt{6}\) and \(\beta=5-2\sqrt{6}\), what is \(\alpha\beta\)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

(\alpha\beta=25-\(2\sqrt{6}\)2=25-24=1). In exams square terms correctly in conjugate multiplication.

Step 2

Why this answer is correct

The correct answer is A. (1). (\alpha\beta=25-\(2\sqrt{6}\)2=25-24=1). In exams square terms correctly in conjugate multiplication.

Step 3

Exam Tip

(\alpha\beta=25-\(2\sqrt{6}\)2=25-24=1) है। परीक्षा में संयुग्मी गुणन में वर्ग सही करें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(\alpha=5+2\sqrt{6}\) और \(\beta=5-2\sqrt{6}\), तो \(\alpha\beta\) क्या है? / If \(\alpha=5+2\sqrt{6}\) and \(\beta=5-2\sqrt{6}\), what is \(\alpha\beta\)?

Correct Answer: A. (1). Explanation: (\alpha\beta=25-\(2\sqrt{6}\)2=25-24=1) है। परीक्षा में संयुग्मी गुणन में वर्ग सही करें। / (\alpha\beta=25-\(2\sqrt{6}\)2=25-24=1). In exams square terms correctly in conjugate multiplication.

Which concept should I revise for this Mathematics MCQ?

(\alpha\beta=25-\(2\sqrt{6}\)2=25-24=1). In exams square terms correctly in conjugate multiplication.

What exam hint can help solve this Mathematics question?

(\alpha\beta=25-\(2\sqrt{6}\)2=25-24=1) है। परीक्षा में संयुग्मी गुणन में वर्ग सही करें।

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