द्विघात (p(x)=x-2+2x-15) का ग्राफ (x)-अक्ष को किन (x)-मानों पर काटेगा?
At which (x)-values will the graph of (p(x)=x-2+2x-15) cut the (x)-axis?
Explanation opens after your attempt
A. (3) और (-5)(3) and (-5)
Concept
(x-2+2x-15=(x+5)(x-3)). Zeroes are the (x)-values of (x)-axis intersections.
Why this answer is correct
The correct answer is A. (3) और (-5) / (3) and (-5). (x-2+2x-15=(x+5)(x-3)). Zeroes are the (x)-values of (x)-axis intersections.
Exam Tip
(x-2+2x-15=(x+5)(x-3)) है। शून्यक (x)-अक्ष पर कटान के (x)-मान होते हैं।
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