Medium Mathematics Real Numbers Class 10 Level 21

\(\frac{27}{216}\) को सरल करने के बाद दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After reducing \(\frac{27}{216}\), after how many places will its decimal expansion terminate?

Explanation opens after your attempt
Correct Answer

C. (3) स्थान(3) places

Step 1

Concept

\(\frac{27}{216}=\frac{1}{8}\).

Step 2

Why this answer is correct

\(8=2^3\).

Step 3

Exam Tip

Therefore the decimal terminates after (3) places. चरण 1: \(\frac{27}{216}=\frac{1}{8}\) है। चरण 2: \(8=2^3\) है। चरण 3: इसलिए दशमलव (3) स्थानों पर समाप्त होगा।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{27}{216}\) को सरल करने के बाद दशमलव प्रसार कितने स्थानों पर समाप्त होगा? / After reducing \(\frac{27}{216}\), after how many places will its decimal expansion terminate?

Correct Answer: C. (3) स्थान / (3) places. Explanation: चरण 1: \(\frac{27}{216}=\frac{1}{8}\) है। चरण 2: \(8=2^3\) है। चरण 3: इसलिए दशमलव (3) स्थानों पर समाप्त होगा। / Step 1: \(\frac{27}{216}=\frac{1}{8}\). Step 2: \(8=2^3\). Step 3: Therefore the decimal terminates after (3) places.

Which concept should I revise for this Mathematics MCQ?

\(\frac{27}{216}=\frac{1}{8}\).

What exam hint can help solve this Mathematics question?

Therefore the decimal terminates after (3) places. चरण 1: \(\frac{27}{216}=\frac{1}{8}\) है। चरण 2: \(8=2^3\) है। चरण 3: इसलिए दशमलव (3) स्थानों पर समाप्त होगा।

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