Expert Mathematics Real Numbers Class 10 Level 20

\(\frac{5^4\cdot 7}{2^6\cdot 5^7\cdot 7}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After how many decimal places will \(\frac{5^4\cdot 7}{2^6\cdot 5^7\cdot 7}\) terminate?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

After cancellation, the denominator becomes \(2^6\cdot 5^3\). The larger exponent is (6), so the decimal terminates after (6) places.

Step 2

Why this answer is correct

The correct answer is C. (6). After cancellation, the denominator becomes \(2^6\cdot 5^3\). The larger exponent is (6), so the decimal terminates after (6) places.

Step 3

Exam Tip

कटौती के बाद हर \(2^6\cdot 5^3\) बचेगा। बड़ी घात (6) है इसलिए दशमलव (6) स्थानों पर समाप्त होगा।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{5^4\cdot 7}{2^6\cdot 5^7\cdot 7}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा? / After how many decimal places will \(\frac{5^4\cdot 7}{2^6\cdot 5^7\cdot 7}\) terminate?

Correct Answer: C. (6). Explanation: कटौती के बाद हर \(2^6\cdot 5^3\) बचेगा। बड़ी घात (6) है इसलिए दशमलव (6) स्थानों पर समाप्त होगा। / After cancellation, the denominator becomes \(2^6\cdot 5^3\). The larger exponent is (6), so the decimal terminates after (6) places.

Which concept should I revise for this Mathematics MCQ?

After cancellation, the denominator becomes \(2^6\cdot 5^3\). The larger exponent is (6), so the decimal terminates after (6) places.

What exam hint can help solve this Mathematics question?

कटौती के बाद हर \(2^6\cdot 5^3\) बचेगा। बड़ी घात (6) है इसलिए दशमलव (6) स्थानों पर समाप्त होगा।

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