\(x^3+x^{2/5}+1\) बहुपद क्यों नहीं है?

Why is \(x^3+x^{2/5}+1\) not a polynomial?

Explanation opens after your attempt
Correct Answer

C. क्योंकि (x^{25}) की घात पूर्णांक नहीं है / Because the power in \(x^{2 / 5}\) is not an integer

Step 1

Concept

In a polynomial, powers of the variable must be integers. The power in \(x^{2/5}\) is \(\frac{2}{5}\), which is not an integer.

Step 2

Why this answer is correct

The correct answer is C. क्योंकि \(x^{2 / 5}\) की घात पूर्णांक नहीं है / Because the power in \(x^{2 / 5}\) is not an integer. In a polynomial, powers of the variable must be integers. The power in \(x^{2/5}\) is \(\frac{2}{5}\), which is not an integer.

Step 3

Exam Tip

बहुपद में चर की घातें पूर्णांक होनी चाहिए। \(x^{2/5}\) की घात \(\frac{2}{5}\) है, जो पूर्णांक नहीं है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(x^3+x^{2/5}+1\) बहुपद क्यों नहीं है? / Why is \(x^3+x^{2/5}+1\) not a polynomial?

Correct Answer: C. क्योंकि \(x^{2 / 5}\) की घात पूर्णांक नहीं है / Because the power in \(x^{2 / 5}\) is not an integer. Explanation: बहुपद में चर की घातें पूर्णांक होनी चाहिए। \(x^{2/5}\) की घात \(\frac{2}{5}\) है, जो पूर्णांक नहीं है। / In a polynomial, powers of the variable must be integers. The power in \(x^{2/5}\) is \(\frac{2}{5}\), which is not an integer.

Which concept should I revise for this Mathematics MCQ?

In a polynomial, powers of the variable must be integers. The power in \(x^{2/5}\) is \(\frac{2}{5}\), which is not an integer.

What exam hint can help solve this Mathematics question?

बहुपद में चर की घातें पूर्णांक होनी चाहिए। \(x^{2/5}\) की घात \(\frac{2}{5}\) है, जो पूर्णांक नहीं है।