\(x^2+x^{1/2}+1\) बहुपद क्यों नहीं है?

Why is \(x^2+x^{1/2}+1\) not a polynomial?

Explanation opens after your attempt
Correct Answer

B. क्योंकि (x^{12}) की घात पूर्णांक नहीं है / Because the power in \(x^{1 / 2}\) is not an integer

Step 1

Concept

In a polynomial, powers of the variable must be integers. \(x^{1/2}\) has power \(\frac{1}{2}\), so it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is B. क्योंकि \(x^{1 / 2}\) की घात पूर्णांक नहीं है / Because the power in \(x^{1 / 2}\) is not an integer. In a polynomial, powers of the variable must be integers. \(x^{1/2}\) has power \(\frac{1}{2}\), so it is not a polynomial.

Step 3

Exam Tip

बहुपद में चर की घातें पूर्णांक होनी चाहिए। \(x^{1/2}\) की घात \(\frac{1}{2}\) है इसलिए यह बहुपद नहीं है।

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Mathematics Answer, Explanation and Revision Hints

\(x^2+x^{1/2}+1\) बहुपद क्यों नहीं है? / Why is \(x^2+x^{1/2}+1\) not a polynomial?

Correct Answer: B. क्योंकि \(x^{1 / 2}\) की घात पूर्णांक नहीं है / Because the power in \(x^{1 / 2}\) is not an integer. Explanation: बहुपद में चर की घातें पूर्णांक होनी चाहिए। \(x^{1/2}\) की घात \(\frac{1}{2}\) है इसलिए यह बहुपद नहीं है। / In a polynomial, powers of the variable must be integers. \(x^{1/2}\) has power \(\frac{1}{2}\), so it is not a polynomial.

Which concept should I revise for this Mathematics MCQ?

In a polynomial, powers of the variable must be integers. \(x^{1/2}\) has power \(\frac{1}{2}\), so it is not a polynomial.

What exam hint can help solve this Mathematics question?

बहुपद में चर की घातें पूर्णांक होनी चाहिए। \(x^{1/2}\) की घात \(\frac{1}{2}\) है इसलिए यह बहुपद नहीं है।