वर्गमूल सर्पिल में \(\sqrt{6}+1=\sqrt{7}\) लिखना क्यों गलत है?
Why is writing \(\sqrt{6}+1=\sqrt{7}\) wrong in a square root spiral?
Explanation opens after your attempt
Correct Answer
A. क्योंकि नया कर्ण (\sqrt{\(\sqrt{6}\)2+12}) से बनता हैBecause the new hypotenuse is formed by (\sqrt{\(\sqrt{6}\)2+12})
Concept
In a square root spiral, lengths are not added directly. The correct method is Pythagoras theorem.
Why this answer is correct
The correct answer is A. क्योंकि नया कर्ण (\sqrt{\(\sqrt{6}\)2+12}) से बनता है / Because the new hypotenuse is formed by (\sqrt{\(\sqrt{6}\)2+12}). In a square root spiral, lengths are not added directly. The correct method is Pythagoras theorem.
Exam Tip
वर्गमूल सर्पिल में सीधे लंबाइयाँ नहीं जोड़ी जातीं। सही तरीका पाइथागोरस प्रमेय है।
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