\(\sqrt{2}\) के प्रमाण में (\gcd(x,y)=1) लिखना क्यों निर्णायक है?

Why is writing (\gcd(x,y)=1) decisive in the proof of \(\sqrt{2}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. क्योंकि अंत में (x,y) दोनों (2) से विभाज्य मिलते हैंBecause finally both (x,y) are found divisible by (2)

Step 1

Concept

(\gcd(x,y)=1) is the lowest-form condition. Common factor (2) in both conflicts with it.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि अंत में (x,y) दोनों (2) से विभाज्य मिलते हैं / Because finally both (x,y) are found divisible by (2). (\gcd(x,y)=1) is the lowest-form condition. Common factor (2) in both conflicts with it.

Step 3

Exam Tip

(\gcd(x,y)=1) सरलतम रूप की शर्त है। दोनों में (2) सामान्य मिलना इसी से टकराता है।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{2}\) के प्रमाण में (\gcd(x,y)=1) लिखना क्यों निर्णायक है? / Why is writing (\gcd(x,y)=1) decisive in the proof of \(\sqrt{2}\)?

Correct Answer: A. क्योंकि अंत में (x,y) दोनों (2) से विभाज्य मिलते हैं / Because finally both (x,y) are found divisible by (2). Explanation: (\gcd(x,y)=1) सरलतम रूप की शर्त है। दोनों में (2) सामान्य मिलना इसी से टकराता है। / (\gcd(x,y)=1) is the lowest-form condition. Common factor (2) in both conflicts with it.

Which concept should I revise for this Mathematics MCQ?

(\gcd(x,y)=1) is the lowest-form condition. Common factor (2) in both conflicts with it.

What exam hint can help solve this Mathematics question?

(\gcd(x,y)=1) सरलतम रूप की शर्त है। दोनों में (2) सामान्य मिलना इसी से टकराता है।