\(\sqrt{3}\) के प्रमाण में केवल (u) का (3) से विभाज्य होना अंतिम विरोधाभास क्यों नहीं है?

Why is only (u) being divisible by (3) not the final contradiction in the proof of \(\sqrt{3}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. क्योंकि (v) को भी (3) से विभाज्य सिद्ध करना जरूरी हैBecause (v) must also be proved divisible by (3)

Step 1

Concept

Contradiction with coprime condition occurs only when both (u) and (v) are divisible by (3).

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (v) को भी (3) से विभाज्य सिद्ध करना जरूरी है / Because (v) must also be proved divisible by (3). Contradiction with coprime condition occurs only when both (u) and (v) are divisible by (3).

Step 3

Exam Tip

सहभाज्य शर्त से विरोधाभास तभी बनेगा जब (u) और (v) दोनों (3) से विभाज्य मिलें।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{3}\) के प्रमाण में केवल (u) का (3) से विभाज्य होना अंतिम विरोधाभास क्यों नहीं है? / Why is only (u) being divisible by (3) not the final contradiction in the proof of \(\sqrt{3}\)?

Correct Answer: A. क्योंकि (v) को भी (3) से विभाज्य सिद्ध करना जरूरी है / Because (v) must also be proved divisible by (3). Explanation: सहभाज्य शर्त से विरोधाभास तभी बनेगा जब (u) और (v) दोनों (3) से विभाज्य मिलें। / Contradiction with coprime condition occurs only when both (u) and (v) are divisible by (3).

Which concept should I revise for this Mathematics MCQ?

Contradiction with coprime condition occurs only when both (u) and (v) are divisible by (3).

What exam hint can help solve this Mathematics question?

सहभाज्य शर्त से विरोधाभास तभी बनेगा जब (u) और (v) दोनों (3) से विभाज्य मिलें।