व्यंजक \(\frac{x^2+1}{x}\) बहुपद क्यों नहीं है?

Why is \(\frac{x^2+1}{x}\) not a polynomial?

Explanation opens after your attempt
Correct Answer

B. क्योंकि चर हर में हैBecause the variable is in the denominator

Step 1

Concept

When the variable is in the denominator, a negative power may appear. Negative powers of the variable are not valid in a polynomial.

Step 2

Why this answer is correct

The correct answer is B. क्योंकि चर हर में है / Because the variable is in the denominator. When the variable is in the denominator, a negative power may appear. Negative powers of the variable are not valid in a polynomial.

Step 3

Exam Tip

चर हर में आने पर ऋणात्मक घात बन सकती है। बहुपद में चर की ऋणात्मक घात मान्य नहीं होती।

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Mathematics Answer, Explanation and Revision Hints

व्यंजक \(\frac{x^2+1}{x}\) बहुपद क्यों नहीं है? / Why is \(\frac{x^2+1}{x}\) not a polynomial?

Correct Answer: B. क्योंकि चर हर में है / Because the variable is in the denominator. Explanation: चर हर में आने पर ऋणात्मक घात बन सकती है। बहुपद में चर की ऋणात्मक घात मान्य नहीं होती। / When the variable is in the denominator, a negative power may appear. Negative powers of the variable are not valid in a polynomial.

Which concept should I revise for this Mathematics MCQ?

When the variable is in the denominator, a negative power may appear. Negative powers of the variable are not valid in a polynomial.

What exam hint can help solve this Mathematics question?

चर हर में आने पर ऋणात्मक घात बन सकती है। बहुपद में चर की ऋणात्मक घात मान्य नहीं होती।